Convert barrel of oil to ton of oil
Learn how to convert
1
barrel of oil to
ton of oil
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(barrel \text{ } of \text{ } oil\right)={\color{rgb(20,165,174)} x}\left(ton \text{ } of \text{ } oil\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(barrel \text{ } of \text{ } oil\right) = {\color{rgb(89,182,91)} 6.1178632 \times 10^{9}\left(joule\right)} = {\color{rgb(89,182,91)} 6.1178632 \times 10^{9}\left(J\right)}\)
\(\text{Right side: 1.0 } \left(ton \text{ } of \text{ } oil\right) = {\color{rgb(125,164,120)} 4.184 \times 10^{10}\left(joule\right)} = {\color{rgb(125,164,120)} 4.184 \times 10^{10}\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(barrel \text{ } of \text{ } oil\right)={\color{rgb(20,165,174)} x}\left(ton \text{ } of \text{ } oil\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 6.1178632 \times 10^{9}} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.184 \times 10^{10}}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 6.1178632 \times 10^{9}} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.184 \times 10^{10}} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 6.1178632 \times 10^{9}} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.184 \times 10^{10}} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(6.1178632 \times 10^{9} = {\color{rgb(20,165,174)} x} \times 4.184 \times 10^{10}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(6.1178632 \times {\color{rgb(255,204,153)} \cancel{10^{9}}} = {\color{rgb(20,165,174)} x} \times 4.184 \times {\color{rgb(255,204,153)} \cancelto{10}{10^{10}}}\)
\(\text{Simplify}\)
\(6.1178632 = {\color{rgb(20,165,174)} x} \times 4.184 \times 10.0\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.184 \times 10.0 = 6.1178632\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.184 \times 10.0}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.184 \times 10.0 \times \dfrac{1.0}{4.184 \times 10.0} = 6.1178632 \times \dfrac{1.0}{4.184 \times 10.0}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.184}} \times {\color{rgb(99,194,222)} \cancel{10.0}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.184}} \times {\color{rgb(99,194,222)} \cancel{10.0}}} = 6.1178632 \times \dfrac{1.0}{4.184 \times 10.0}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{6.1178632}{4.184 \times 10.0}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.1462204398\approx1.4622 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(barrel \text{ } of \text{ } oil\right)\approx{\color{rgb(20,165,174)} 1.4622 \times 10^{-1}}\left(ton \text{ } of \text{ } oil\right)\)
