Convert (gram • meter) / square second to pond

Learn how to convert 1 (gram • meter) / square second to pond step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(\dfrac{gram \times meter}{square \text{ } second}\right)={\color{rgb(20,165,174)} x}\left(pond\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(newton\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{gram \times meter}{square \text{ } second}\right) = {\color{rgb(89,182,91)} 10^{-3}\left(newton\right)} = {\color{rgb(89,182,91)} 10^{-3}\left(N\right)}\)
\(\text{Right side: 1.0 } \left(pond\right) = {\color{rgb(125,164,120)} 9.80665 \times 10^{-3}\left(newton\right)} = {\color{rgb(125,164,120)} 9.80665 \times 10^{-3}\left(N\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{gram \times meter}{square \text{ } second}\right)={\color{rgb(20,165,174)} x}\left(pond\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{-3}} \times {\color{rgb(89,182,91)} \left(newton\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 9.80665 \times 10^{-3}}} \times {\color{rgb(125,164,120)} \left(newton\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 10^{-3}} \cdot {\color{rgb(89,182,91)} \left(N\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 9.80665 \times 10^{-3}} \cdot {\color{rgb(125,164,120)} \left(N\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{-3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(N\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 9.80665 \times 10^{-3}} \times {\color{rgb(125,164,120)} \cancel{\left(N\right)}}\)
\(\text{Conversion Equation}\)
\(10^{-3} = {\color{rgb(20,165,174)} x} \times 9.80665 \times 10^{-3}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\({\color{rgb(255,204,153)} \cancel{10^{-3}}} = {\color{rgb(20,165,174)} x} \times 9.80665 \times {\color{rgb(255,204,153)} \cancel{10^{-3}}}\)
\(\text{Simplify}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 9.80665\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 9.80665 = 1.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{9.80665}\right)\)
\({\color{rgb(20,165,174)} x} \times 9.80665 \times \dfrac{1.0}{9.80665} = \times \dfrac{1.0}{9.80665}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{9.80665}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{9.80665}}} = \dfrac{1.0}{9.80665}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.0}{9.80665}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.1019716213\approx1.0197 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{gram \times meter}{square \text{ } second}\right)\approx{\color{rgb(20,165,174)} 1.0197 \times 10^{-1}}\left(pond\right)\)

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