Convert (ohm • ampere) / second to rydberg
Learn how to convert
1
(ohm • ampere) / second to
rydberg
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{ohm \times ampere}{second}\right)={\color{rgb(20,165,174)} x}\left(rydberg\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{ohm \times ampere}{second}\right) = {\color{rgb(89,182,91)} 1.0\left(joule\right)} = {\color{rgb(89,182,91)} 1.0\left(J\right)}\)
\(\text{Right side: 1.0 } \left(rydberg\right) = {\color{rgb(125,164,120)} 2.179872 \times 10^{-18}\left(joule\right)} = {\color{rgb(125,164,120)} 2.179872 \times 10^{-18}\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{ohm \times ampere}{second}\right)={\color{rgb(20,165,174)} x}\left(rydberg\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 2.179872 \times 10^{-18}}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 2.179872 \times 10^{-18}} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 2.179872 \times 10^{-18}} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 2.179872 \times 10^{-18}\)
\(\text{Simplify}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 2.179872 \times 10^{-18}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 2.179872 \times 10^{-18} = 1.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{2.179872 \times 10^{-18}}\right)\)
\({\color{rgb(20,165,174)} x} \times 2.179872 \times 10^{-18} \times \dfrac{1.0}{2.179872 \times 10^{-18}} = 1.0 \times \dfrac{1.0}{2.179872 \times 10^{-18}}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{2.179872}} \times {\color{rgb(99,194,222)} \cancel{10^{-18}}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{2.179872}} \times {\color{rgb(99,194,222)} \cancel{10^{-18}}}} = 1.0 \times \dfrac{1.0}{2.179872 \times 10^{-18}}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.0}{2.179872 \times 10^{-18}}\)
Rewrite equation
\(\dfrac{1.0}{10^{-18}}\text{ can be rewritten to }10^{18}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{18}}{2.179872}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx4.5874253167 \times 10^{17}\approx4.5874 \times 10^{17}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{ohm \times ampere}{second}\right)\approx{\color{rgb(20,165,174)} 4.5874 \times 10^{17}}\left(rydberg\right)\)
