Convert BTU / pound to BTU / pound
Learn how to convert
1
BTU / pound to
BTU / pound
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{BTU}{pound}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{BTU}{pound}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{joule}{{\color{rgb(230,179,255)} kilo}gram}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{BTU}{pound}\right) = {\color{rgb(89,182,91)} \dfrac{1055.05585262}{0.45359237}\left(\dfrac{joule}{{\color{rgb(230,179,255)} kilo}gram}\right)} = {\color{rgb(89,182,91)} \dfrac{1055.05585262}{0.45359237}\left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{BTU}{pound}\right) = {\color{rgb(125,164,120)} \dfrac{1054.5}{0.45359237}\left(\dfrac{joule}{{\color{rgb(230,179,255)} kilo}gram}\right)} = {\color{rgb(125,164,120)} \dfrac{1054.5}{0.45359237}\left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{BTU}{pound}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{BTU}{pound}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1055.05585262}{0.45359237}} \times {\color{rgb(89,182,91)} \left(\dfrac{joule}{{\color{rgb(230,179,255)} kilo}gram}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{1054.5}{0.45359237}}} \times {\color{rgb(125,164,120)} \left(\dfrac{joule}{{\color{rgb(230,179,255)} kilo}gram}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{1055.05585262}{0.45359237}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{1054.5}{0.45359237}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1055.05585262}{0.45359237}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{1054.5}{0.45359237}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{J}{{\color{rgb(230,179,255)} k}g}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{1055.05585262}{0.45359237} = {\color{rgb(20,165,174)} x} \times \dfrac{1054.5}{0.45359237}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(\dfrac{1055.05585262}{{\color{rgb(255,204,153)} \cancel{0.45359237}}} = {\color{rgb(20,165,174)} x} \times \dfrac{1054.5}{{\color{rgb(255,204,153)} \cancel{0.45359237}}}\)
\(\text{Simplify}\)
\(1055.05585262 = {\color{rgb(20,165,174)} x} \times 1054.5\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 1054.5 = 1055.05585262\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{1054.5}\right)\)
\({\color{rgb(20,165,174)} x} \times 1054.5 \times \dfrac{1.0}{1054.5} = 1055.05585262 \times \dfrac{1.0}{1054.5}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{1054.5}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{1054.5}}} = 1055.05585262 \times \dfrac{1.0}{1054.5}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1055.05585262}{1054.5}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx1.0005271243\approx1.0005\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{BTU}{pound}\right)\approx{\color{rgb(20,165,174)} 1.0005}\left(\dfrac{BTU}{pound}\right)\)
