Convert Newton • meter to foot-pound • pound force
Learn how to convert
1
Newton • meter to
foot-pound • pound force
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(Newton \times meter\right)={\color{rgb(20,165,174)} x}\left(foot-pound \times pound \text{ } force\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(Newton \times meter\right) = {\color{rgb(89,182,91)} 1.0\left(joule\right)} = {\color{rgb(89,182,91)} 1.0\left(J\right)}\)
\(\text{Right side: 1.0 } \left(foot-pound \times pound \text{ } force\right) = {\color{rgb(125,164,120)} 1.3558179483314\left(joule\right)} = {\color{rgb(125,164,120)} 1.3558179483314\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(Newton \times meter\right)={\color{rgb(20,165,174)} x}\left(foot-pound \times pound \text{ } force\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 1.3558179483314}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 1.3558179483314} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 1.3558179483314} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 1.3558179483314\)
\(\text{Simplify}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 1.3558179483314\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 1.3558179483314 = 1.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{1.3558179483314}\right)\)
\({\color{rgb(20,165,174)} x} \times 1.3558179483314 \times \dfrac{1.0}{1.3558179483314} = 1.0 \times \dfrac{1.0}{1.3558179483314}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{1.3558179483314}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{1.3558179483314}}} = 1.0 \times \dfrac{1.0}{1.3558179483314}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.0}{1.3558179483314}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.7375621493\approx7.3756 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(Newton \times meter\right)\approx{\color{rgb(20,165,174)} 7.3756 \times 10^{-1}}\left(foot-pound \times pound \text{ } force\right)\)
