Convert cubic foot of natural gas to (gram • meter) / second
Learn how to convert
1
cubic foot of natural gas to
(gram • meter) / second
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)={\color{rgb(20,165,174)} x}\left(\dfrac{gram \times meter}{second}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right) = {\color{rgb(89,182,91)} 1055055.85262\left(joule\right)} = {\color{rgb(89,182,91)} 1055055.85262\left(J\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{gram \times meter}{second}\right) = {\color{rgb(125,164,120)} 10^{-3}\left(joule\right)} = {\color{rgb(125,164,120)} 10^{-3}\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)={\color{rgb(20,165,174)} x}\left(\dfrac{gram \times meter}{second}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1055055.85262} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 10^{-3}}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1055055.85262} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 10^{-3}} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1055055.85262} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 10^{-3}} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1055055.85262 = {\color{rgb(20,165,174)} x} \times 10^{-3}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 10^{-3} = 1055055.85262\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{10^{-3}}\right)\)
\({\color{rgb(20,165,174)} x} \times 10^{-3} \times \dfrac{1.0}{10^{-3}} = 1055055.85262 \times \dfrac{1.0}{10^{-3}}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{10^{-3}}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{10^{-3}}}} = 1055055.85262 \times \dfrac{1.0}{10^{-3}}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1055055.85262}{10^{-3}}\)
Rewrite equation
\(\dfrac{1.0}{10^{-3}}\text{ can be rewritten to }10^{3}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = 10^{3} \times 1055055.85262\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x} = 1055055852.6\approx1.0551 \times 10^{9}\)
\(\text{Conversion Equation}\)
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)\approx{\color{rgb(20,165,174)} 1.0551 \times 10^{9}}\left(\dfrac{gram \times meter}{second}\right)\)
