Convert cubic foot of natural gas to ton of tnt
Learn how to convert
1
cubic foot of natural gas to
ton of tnt
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)={\color{rgb(20,165,174)} x}\left(ton \text{ } of \text{ } tnt\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right) = {\color{rgb(89,182,91)} 1055055.85262\left(joule\right)} = {\color{rgb(89,182,91)} 1055055.85262\left(J\right)}\)
\(\text{Right side: 1.0 } \left(ton \text{ } of \text{ } tnt\right) = {\color{rgb(125,164,120)} 4.184 \times 10^{9}\left(joule\right)} = {\color{rgb(125,164,120)} 4.184 \times 10^{9}\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)={\color{rgb(20,165,174)} x}\left(ton \text{ } of \text{ } tnt\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1055055.85262} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.184 \times 10^{9}}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1055055.85262} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.184 \times 10^{9}} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1055055.85262} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.184 \times 10^{9}} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1055055.85262 = {\color{rgb(20,165,174)} x} \times 4.184 \times 10^{9}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.184 \times 10^{9} = 1055055.85262\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.184 \times 10^{9}}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.184 \times 10^{9} \times \dfrac{1.0}{4.184 \times 10^{9}} = 1055055.85262 \times \dfrac{1.0}{4.184 \times 10^{9}}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.184}} \times {\color{rgb(99,194,222)} \cancel{10^{9}}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.184}} \times {\color{rgb(99,194,222)} \cancel{10^{9}}}} = 1055055.85262 \times \dfrac{1.0}{4.184 \times 10^{9}}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1055055.85262}{4.184 \times 10^{9}}\)
Rewrite equation
\(\dfrac{1.0}{10^{9}}\text{ can be rewritten to }10^{-9}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-9} \times 1055055.85262}{4.184}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0002521644\approx2.5216 \times 10^{-4}\)
\(\text{Conversion Equation}\)
\(1.0\left(cubic \text{ } foot \text{ } of \text{ } natural \text{ } gas\right)\approx{\color{rgb(20,165,174)} 2.5216 \times 10^{-4}}\left(ton \text{ } of \text{ } tnt\right)\)
