Convert electronvolt to cubic yard of atmosphere
Learn how to convert
1
electronvolt to
cubic yard of atmosphere
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(electronvolt\right)={\color{rgb(20,165,174)} x}\left(cubic \text{ } yard \text{ } of \text{ } atmosphere\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(electronvolt\right) = {\color{rgb(89,182,91)} 1.602176462 \times 10^{-19}\left(joule\right)} = {\color{rgb(89,182,91)} 1.602176462 \times 10^{-19}\left(J\right)}\)
\(\text{Right side: 1.0 } \left(cubic \text{ } yard \text{ } of \text{ } atmosphere\right) = {\color{rgb(125,164,120)} 77468.5209852288\left(joule\right)} = {\color{rgb(125,164,120)} 77468.5209852288\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(electronvolt\right)={\color{rgb(20,165,174)} x}\left(cubic \text{ } yard \text{ } of \text{ } atmosphere\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.602176462 \times 10^{-19}} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 77468.5209852288}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.602176462 \times 10^{-19}} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 77468.5209852288} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.602176462 \times 10^{-19}} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 77468.5209852288} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1.602176462 \times 10^{-19} = {\color{rgb(20,165,174)} x} \times 77468.5209852288\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 77468.5209852288 = 1.602176462 \times 10^{-19}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{77468.5209852288}\right)\)
\({\color{rgb(20,165,174)} x} \times 77468.5209852288 \times \dfrac{1.0}{77468.5209852288} = 1.602176462 \times 10^{-19} \times \dfrac{1.0}{77468.5209852288}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{77468.5209852288}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{77468.5209852288}}} = 1.602176462 \times 10^{-19} \times \dfrac{1.0}{77468.5209852288}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.602176462 \times 10^{-19}}{77468.5209852288}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx2.0681645159 \times 10^{-24}\approx2.0682 \times 10^{-24}\)
\(\text{Conversion Equation}\)
\(1.0\left(electronvolt\right)\approx{\color{rgb(20,165,174)} 2.0682 \times 10^{-24}}\left(cubic \text{ } yard \text{ } of \text{ } atmosphere\right)\)
