Convert gallon atmosphere to calorie
Learn how to convert
1
gallon atmosphere to
calorie
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(gallon \text{ } atmosphere\right)={\color{rgb(20,165,174)} x}\left(calorie\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(gallon \text{ } atmosphere\right) = {\color{rgb(89,182,91)} 383.5568490138\left(joule\right)} = {\color{rgb(89,182,91)} 383.5568490138\left(J\right)}\)
\(\text{Right side: 1.0 } \left(calorie\right) = {\color{rgb(125,164,120)} 4.1868\left(joule\right)} = {\color{rgb(125,164,120)} 4.1868\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(gallon \text{ } atmosphere\right)={\color{rgb(20,165,174)} x}\left(calorie\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 383.5568490138} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.1868}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 383.5568490138} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.1868} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 383.5568490138} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.1868} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(383.5568490138 = {\color{rgb(20,165,174)} x} \times 4.1868\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.1868 = 383.5568490138\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.1868}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.1868 \times \dfrac{1.0}{4.1868} = 383.5568490138 \times \dfrac{1.0}{4.1868}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.1868}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.1868}}} = 383.5568490138 \times \dfrac{1.0}{4.1868}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{383.5568490138}{4.1868}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx91.61097951\approx91.611\)
\(\text{Conversion Equation}\)
\(1.0\left(gallon \text{ } atmosphere\right)\approx{\color{rgb(20,165,174)} 91.611}\left(calorie\right)\)
