Convert gallon to pottle

Learn how to convert 1 gallon to pottle step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(gallon\right)={\color{rgb(20,165,174)} x}\left(pottle\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(cubic \text{ } meter\right)\)
\(\text{Left side: 1.0 } \left(gallon\right) = {\color{rgb(89,182,91)} 4.5424941408 \times 10^{-3}\left(cubic \text{ } meter\right)} = {\color{rgb(89,182,91)} 4.5424941408 \times 10^{-3}\left(m^{3}\right)}\)
\(\text{Right side: 1.0 } \left(pottle\right) = {\color{rgb(125,164,120)} 2.273045 \times 10^{-3}\left(cubic \text{ } meter\right)} = {\color{rgb(125,164,120)} 2.273045 \times 10^{-3}\left(m^{3}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(gallon\right)={\color{rgb(20,165,174)} x}\left(pottle\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 4.5424941408 \times 10^{-3}} \times {\color{rgb(89,182,91)} \left(cubic \text{ } meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 2.273045 \times 10^{-3}}} \times {\color{rgb(125,164,120)} \left(cubic \text{ } meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 4.5424941408 \times 10^{-3}} \cdot {\color{rgb(89,182,91)} \left(m^{3}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 2.273045 \times 10^{-3}} \cdot {\color{rgb(125,164,120)} \left(m^{3}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 4.5424941408 \times 10^{-3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(m^{3}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 2.273045 \times 10^{-3}} \times {\color{rgb(125,164,120)} \cancel{\left(m^{3}\right)}}\)
\(\text{Conversion Equation}\)
\(4.5424941408 \times 10^{-3} = {\color{rgb(20,165,174)} x} \times 2.273045 \times 10^{-3}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(4.5424941408 \times {\color{rgb(255,204,153)} \cancel{10^{-3}}} = {\color{rgb(20,165,174)} x} \times 2.273045 \times {\color{rgb(255,204,153)} \cancel{10^{-3}}}\)
\(\text{Simplify}\)
\(4.5424941408 = {\color{rgb(20,165,174)} x} \times 2.273045\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 2.273045 = 4.5424941408\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{2.273045}\right)\)
\({\color{rgb(20,165,174)} x} \times 2.273045 \times \dfrac{1.0}{2.273045} = 4.5424941408 \times \dfrac{1.0}{2.273045}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{2.273045}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{2.273045}}} = 4.5424941408 \times \dfrac{1.0}{2.273045}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{4.5424941408}{2.273045}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx1.9984180431\approx1.9984\)
\(\text{Conversion Equation}\)
\(1.0\left(gallon\right)\approx{\color{rgb(20,165,174)} 1.9984}\left(pottle\right)\)

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