Convert juchart to fang zhang(方丈)
Learn how to convert
1
juchart to
fang zhang(方丈)
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(juchart\right)={\color{rgb(20,165,174)} x}\left(fang \text{ } zhang(方丈)\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(square \text{ } meter\right)\)
\(\text{Left side: 1.0 } \left(juchart\right) = {\color{rgb(89,182,91)} 4.5 \times 10^{3}\left(square \text{ } meter\right)} = {\color{rgb(89,182,91)} 4.5 \times 10^{3}\left(m^{2}\right)}\)
\(\text{Right side: 1.0 } \left(fang \text{ } zhang(方丈)\right) = {\color{rgb(125,164,120)} \dfrac{10^{2}}{9.0}\left(square \text{ } meter\right)} = {\color{rgb(125,164,120)} \dfrac{10^{2}}{9.0}\left(m^{2}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(juchart\right)={\color{rgb(20,165,174)} x}\left(fang \text{ } zhang(方丈)\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 4.5 \times 10^{3}} \times {\color{rgb(89,182,91)} \left(square \text{ } meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{10^{2}}{9.0}}} \times {\color{rgb(125,164,120)} \left(square \text{ } meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 4.5 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \left(m^{2}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{10^{2}}{9.0}} \cdot {\color{rgb(125,164,120)} \left(m^{2}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 4.5 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(m^{2}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{10^{2}}{9.0}} \times {\color{rgb(125,164,120)} \cancel{\left(m^{2}\right)}}\)
\(\text{Conversion Equation}\)
\(4.5 \times 10^{3} = {\color{rgb(20,165,174)} x} \times \dfrac{10^{2}}{9.0}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(4.5 \times {\color{rgb(255,204,153)} \cancelto{10}{10^{3}}} = {\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{10^{2}}}}{9.0}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{1.0}{9.0} = 4.5 \times 10.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{9.0}{1.0}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{1.0}{9.0} \times \dfrac{9.0}{1.0} = 4.5 \times 10.0 \times \dfrac{9.0}{1.0}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{1.0}} \times {\color{rgb(99,194,222)} \cancel{9.0}}}{{\color{rgb(99,194,222)} \cancel{9.0}} \times {\color{rgb(255,204,153)} \cancel{1.0}}} = 4.5 \times 10.0 \times \dfrac{9.0}{1.0}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = 4.5 \times 10.0 \times 9.0\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x} = 405 = 4.05 \times 10^{2}\)
\(\text{Conversion Equation}\)
\(1.0\left(juchart\right) = {\color{rgb(20,165,174)} 4.05 \times 10^{2}}\left(fang \text{ } zhang(方丈)\right)\)
