Convert mo(毛) to maru(丸)
Learn how to convert
1
mo(毛) to
maru(丸)
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(mo(毛)\right)={\color{rgb(20,165,174)} x}\left(maru(丸)\right)\)
Define the base values of the selected units in relation to the SI unit \(\left({\color{rgb(230,179,255)} kilo}gram\right)\)
\(\text{Left side: 1.0 } \left(mo(毛)\right) = {\color{rgb(89,182,91)} \dfrac{3.0}{8.0 \times 10^{5}}\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(89,182,91)} \dfrac{3.0}{8.0 \times 10^{5}}\left({\color{rgb(230,179,255)} k}g\right)}\)
\(\text{Right side: 1.0 } \left(maru(丸)\right) = {\color{rgb(125,164,120)} 30.0\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(125,164,120)} 30.0\left({\color{rgb(230,179,255)} k}g\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(mo(毛)\right)={\color{rgb(20,165,174)} x}\left(maru(丸)\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{3.0}{8.0 \times 10^{5}}} \times {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 30.0}} \times {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} kilo}gram\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{3.0}{8.0 \times 10^{5}}} \cdot {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} k}g\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 30.0} \cdot {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} k}g\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{3.0}{8.0 \times 10^{5}}} \cdot {\color{rgb(89,182,91)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 30.0} \times {\color{rgb(125,164,120)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{3.0}{8.0 \times 10^{5}} = {\color{rgb(20,165,174)} x} \times 30.0\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 30.0 = \dfrac{3.0}{8.0 \times 10^{5}}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{30.0}\right)\)
\({\color{rgb(20,165,174)} x} \times 30.0 \times \dfrac{1.0}{30.0} = \dfrac{3.0}{8.0 \times 10^{5}} \times \dfrac{1.0}{30.0}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{30.0}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{30.0}}} = \dfrac{3.0 \times 1.0}{8.0 \times 10^{5} \times 30.0}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{3.0}{8.0 \times 10^{5} \times 30.0}\)
Rewrite equation
\(\dfrac{1.0}{10^{5}}\text{ can be rewritten to }10^{-5}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-5} \times 3.0}{8.0 \times 30.0}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x} = 1.25 \times 10^{-7}\)
\(\text{Conversion Equation}\)
\(1.0\left(mo(毛)\right) = {\color{rgb(20,165,174)} 1.25 \times 10^{-7}}\left(maru(丸)\right)\)
