# Convert mole / barrel to mole / cubic yard

Learn how to convert 1 mole / barrel to mole / cubic yard step by step.

## Calculation Breakdown

Set up the equation
$$1.0\left(\dfrac{mole}{barrel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{mole}{cubic \text{ } yard}\right)$$
Define the base values of the selected units in relation to the SI unit $$\left(\dfrac{mole}{cubic \text{ } meter}\right)$$
$$\text{Left side: 1.0 } \left(\dfrac{mole}{barrel}\right) = {\color{rgb(89,182,91)} \dfrac{1.0}{0.16365924}\left(\dfrac{mole}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{1.0}{0.16365924}\left(\dfrac{mol}{m^{3}}\right)}$$
$$\text{Right side: 1.0 } \left(\dfrac{mole}{cubic \text{ } yard}\right) = {\color{rgb(125,164,120)} \dfrac{1.0}{0.764554857984}\left(\dfrac{mole}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{1.0}{0.764554857984}\left(\dfrac{mol}{m^{3}}\right)}$$
Insert known values into the conversion equation to determine $${\color{rgb(20,165,174)} x}$$
$$1.0\left(\dfrac{mole}{barrel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{mole}{cubic \text{ } yard}\right)$$
$$\text{Insert known values } =>$$
$$1.0 \times {\color{rgb(89,182,91)} \dfrac{1.0}{0.16365924}} \times {\color{rgb(89,182,91)} \left(\dfrac{mole}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{1.0}{0.764554857984}}} \times {\color{rgb(125,164,120)} \left(\dfrac{mole}{cubic \text{ } meter}\right)}$$
$$\text{Or}$$
$$1.0 \cdot {\color{rgb(89,182,91)} \dfrac{1.0}{0.16365924}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{mol}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{1.0}{0.764554857984}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{mol}{m^{3}}\right)}$$
$$\text{Cancel SI units}$$
$$1.0 \times {\color{rgb(89,182,91)} \dfrac{1.0}{0.16365924}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{mol}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{1.0}{0.764554857984}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{mol}{m^{3}}\right)}}$$
$$\text{Conversion Equation}$$
$$\dfrac{1.0}{0.16365924} = {\color{rgb(20,165,174)} x} \times \dfrac{1.0}{0.764554857984}$$
Cancel factors on both sides
$$\text{Cancel factors}$$
$$\dfrac{{\color{rgb(255,204,153)} \cancel{1.0}}}{0.16365924} = {\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{1.0}}}{0.764554857984}$$
Switch sides
$${\color{rgb(20,165,174)} x} \times \dfrac{1.0}{0.764554857984} = \dfrac{1.0}{0.16365924}$$
Isolate $${\color{rgb(20,165,174)} x}$$
Multiply both sides by $$\left(\dfrac{0.764554857984}{1.0}\right)$$
$${\color{rgb(20,165,174)} x} \times \dfrac{1.0}{0.764554857984} \times \dfrac{0.764554857984}{1.0} = \dfrac{1.0}{0.16365924} \times \dfrac{0.764554857984}{1.0}$$
$$\text{Cancel}$$
$${\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{1.0}} \times {\color{rgb(99,194,222)} \cancel{0.764554857984}}}{{\color{rgb(99,194,222)} \cancel{0.764554857984}} \times {\color{rgb(255,204,153)} \cancel{1.0}}} = \dfrac{{\color{rgb(255,204,153)} \cancel{1.0}} \times 0.764554857984}{0.16365924 \times {\color{rgb(255,204,153)} \cancel{1.0}}}$$
$$\text{Simplify}$$
$${\color{rgb(20,165,174)} x} = \dfrac{0.764554857984}{0.16365924}$$
Solve $${\color{rgb(20,165,174)} x}$$
$${\color{rgb(20,165,174)} x}\approx4.6716265943\approx4.6716$$
$$\text{Conversion Equation}$$
$$1.0\left(\dfrac{mole}{barrel}\right)\approx{\color{rgb(20,165,174)} 4.6716}\left(\dfrac{mole}{cubic \text{ } yard}\right)$$