# Convert pound-force • foot to pound-force • inch

Learn how to convert 1 pound-force • foot to pound-force • inch step by step.

## Calculation Breakdown

Set up the equation
$$1.0\left(pound-force \times foot\right)={\color{rgb(20,165,174)} x}\left(pound-force \times inch\right)$$
Define the base values of the selected units in relation to the SI unit $$\left(newton \times meter\right)$$
$$\text{Left side: 1.0 } \left(pound-force \times foot\right) = {\color{rgb(89,182,91)} 1.3558179483314\left(newton \times meter\right)} = {\color{rgb(89,182,91)} 1.3558179483314\left(N \cdot m\right)}$$
$$\text{Right side: 1.0 } \left(pound-force \times inch\right) = {\color{rgb(125,164,120)} 0.112984829027617\left(newton \times meter\right)} = {\color{rgb(125,164,120)} 0.112984829027617\left(N \cdot m\right)}$$
Insert known values into the conversion equation to determine $${\color{rgb(20,165,174)} x}$$
$$1.0\left(pound-force \times foot\right)={\color{rgb(20,165,174)} x}\left(pound-force \times inch\right)$$
$$\text{Insert known values } =>$$
$$1.0 \times {\color{rgb(89,182,91)} 1.3558179483314} \times {\color{rgb(89,182,91)} \left(newton \times meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 0.112984829027617}} \times {\color{rgb(125,164,120)} \left(newton \times meter\right)}$$
$$\text{Or}$$
$$1.0 \cdot {\color{rgb(89,182,91)} 1.3558179483314} \cdot {\color{rgb(89,182,91)} \left(N \cdot m\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 0.112984829027617} \cdot {\color{rgb(125,164,120)} \left(N \cdot m\right)}$$
$$\text{Cancel SI units}$$
$$1.0 \times {\color{rgb(89,182,91)} 1.3558179483314} \cdot {\color{rgb(89,182,91)} \cancel{\left(N \cdot m\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 0.112984829027617} \times {\color{rgb(125,164,120)} \cancel{\left(N \cdot m\right)}}$$
$$\text{Conversion Equation}$$
$$1.3558179483314 = {\color{rgb(20,165,174)} x} \times 0.112984829027617$$
Switch sides
$${\color{rgb(20,165,174)} x} \times 0.112984829027617 = 1.3558179483314$$
Isolate $${\color{rgb(20,165,174)} x}$$
Multiply both sides by $$\left(\dfrac{1.0}{0.112984829027617}\right)$$
$${\color{rgb(20,165,174)} x} \times 0.112984829027617 \times \dfrac{1.0}{0.112984829027617} = 1.3558179483314 \times \dfrac{1.0}{0.112984829027617}$$
$$\text{Cancel}$$
$${\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{0.112984829027617}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{0.112984829027617}}} = 1.3558179483314 \times \dfrac{1.0}{0.112984829027617}$$
$$\text{Simplify}$$
$${\color{rgb(20,165,174)} x} = \dfrac{1.3558179483314}{0.112984829027617}$$
Solve $${\color{rgb(20,165,174)} x}$$
$${\color{rgb(20,165,174)} x} = 12$$
$$\text{Conversion Equation}$$
$$1.0\left(pound-force \times foot\right) = {\color{rgb(20,165,174)} 12}\left(pound-force \times inch\right)$$

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