Convert pound / fluid-ounce to ton / bushel
Learn how to convert
1
pound / fluid-ounce to
ton / bushel
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ton}{bushel}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{pound}{fluid-ounce}\right) = {\color{rgb(89,182,91)} \dfrac{45359.237}{2.95735295625}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{45359.237}{2.95735295625}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{ton}{bushel}\right) = {\color{rgb(125,164,120)} \dfrac{10^{5}}{3.523907016688}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{10^{5}}{3.523907016688}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ton}{bushel}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45359.237}{2.95735295625}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{10^{5}}{3.523907016688}}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{45359.237}{2.95735295625}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{10^{5}}{3.523907016688}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45359.237}{2.95735295625}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{10^{5}}{3.523907016688}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{45359.237}{2.95735295625} = {\color{rgb(20,165,174)} x} \times \dfrac{10^{5}}{3.523907016688}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{10^{5}}{3.523907016688} = \dfrac{45359.237}{2.95735295625}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{3.523907016688}{10^{5}}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{10^{5}}{3.523907016688} \times \dfrac{3.523907016688}{10^{5}} = \dfrac{45359.237}{2.95735295625} \times \dfrac{3.523907016688}{10^{5}}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{10^{5}}} \times {\color{rgb(99,194,222)} \cancel{3.523907016688}}}{{\color{rgb(99,194,222)} \cancel{3.523907016688}} \times {\color{rgb(255,204,153)} \cancel{10^{5}}}} = \dfrac{45359.237 \times 3.523907016688}{2.95735295625 \times 10^{5}}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{45359.237 \times 3.523907016688}{2.95735295625 \times 10^{5}}\)
Rewrite equation
\(\dfrac{1.0}{10^{5}}\text{ can be rewritten to }10^{-5}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-5} \times 45359.237 \times 3.523907016688}{2.95735295625}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.5404892006\approx5.4049 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)\approx{\color{rgb(20,165,174)} 5.4049 \times 10^{-1}}\left(\dfrac{ton}{bushel}\right)\)
