Convert rai to football field

Learn how to convert 1 rai to football field step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(rai\right)={\color{rgb(20,165,174)} x}\left(football \text{ } field\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(square \text{ } meter\right)\)
\(\text{Left side: 1.0 } \left(rai\right) = {\color{rgb(89,182,91)} 1.6 \times 10^{3}\left(square \text{ } meter\right)} = {\color{rgb(89,182,91)} 1.6 \times 10^{3}\left(m^{2}\right)}\)
\(\text{Right side: 1.0 } \left(football \text{ } field\right) = {\color{rgb(125,164,120)} 8.15 \times 10^{3}\left(square \text{ } meter\right)} = {\color{rgb(125,164,120)} 8.15 \times 10^{3}\left(m^{2}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(rai\right)={\color{rgb(20,165,174)} x}\left(football \text{ } field\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.6 \times 10^{3}} \times {\color{rgb(89,182,91)} \left(square \text{ } meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 8.15 \times 10^{3}}} \times {\color{rgb(125,164,120)} \left(square \text{ } meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \left(m^{2}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 8.15 \times 10^{3}} \cdot {\color{rgb(125,164,120)} \left(m^{2}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(m^{2}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 8.15 \times 10^{3}} \times {\color{rgb(125,164,120)} \cancel{\left(m^{2}\right)}}\)
\(\text{Conversion Equation}\)
\(1.6 \times 10^{3} = {\color{rgb(20,165,174)} x} \times 8.15 \times 10^{3}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(1.6 \times {\color{rgb(255,204,153)} \cancel{10^{3}}} = {\color{rgb(20,165,174)} x} \times 8.15 \times {\color{rgb(255,204,153)} \cancel{10^{3}}}\)
\(\text{Simplify}\)
\(1.6 = {\color{rgb(20,165,174)} x} \times 8.15\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 8.15 = 1.6\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{8.15}\right)\)
\({\color{rgb(20,165,174)} x} \times 8.15 \times \dfrac{1.0}{8.15} = 1.6 \times \dfrac{1.0}{8.15}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{8.15}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{8.15}}} = 1.6 \times \dfrac{1.0}{8.15}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.6}{8.15}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.1963190184\approx1.9632 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(rai\right)\approx{\color{rgb(20,165,174)} 1.9632 \times 10^{-1}}\left(football \text{ } field\right)\)

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