Convert sthene to pound-force
Learn how to convert
1
sthene to
pound-force
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(sthene\right)={\color{rgb(20,165,174)} x}\left(pound-force\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(newton\right)\)
\(\text{Left side: 1.0 } \left(sthene\right) = {\color{rgb(89,182,91)} 10^{3}\left(newton\right)} = {\color{rgb(89,182,91)} 10^{3}\left(N\right)}\)
\(\text{Right side: 1.0 } \left(pound-force\right) = {\color{rgb(125,164,120)} 4.4482216152605\left(newton\right)} = {\color{rgb(125,164,120)} 4.4482216152605\left(N\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(sthene\right)={\color{rgb(20,165,174)} x}\left(pound-force\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{3}} \times {\color{rgb(89,182,91)} \left(newton\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.4482216152605}} \times {\color{rgb(125,164,120)} \left(newton\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 10^{3}} \cdot {\color{rgb(89,182,91)} \left(N\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.4482216152605} \cdot {\color{rgb(125,164,120)} \left(N\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(N\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.4482216152605} \times {\color{rgb(125,164,120)} \cancel{\left(N\right)}}\)
\(\text{Conversion Equation}\)
\(10^{3} = {\color{rgb(20,165,174)} x} \times 4.4482216152605\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.4482216152605 = 10^{3}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.4482216152605}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.4482216152605 \times \dfrac{1.0}{4.4482216152605} = 10^{3} \times \dfrac{1.0}{4.4482216152605}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.4482216152605}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.4482216152605}}} = 10^{3} \times \dfrac{1.0}{4.4482216152605}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{3}}{4.4482216152605}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx224.8089431\approx2.2481 \times 10^{2}\)
\(\text{Conversion Equation}\)
\(1.0\left(sthene\right)\approx{\color{rgb(20,165,174)} 2.2481 \times 10^{2}}\left(pound-force\right)\)
