Convert therm to calorie
Learn how to convert
1
therm to
calorie
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(therm\right)={\color{rgb(20,165,174)} x}\left(calorie\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(therm\right) = {\color{rgb(89,182,91)} 105480400.0\left(joule\right)} = {\color{rgb(89,182,91)} 105480400.0\left(J\right)}\)
\(\text{Right side: 1.0 } \left(calorie\right) = {\color{rgb(125,164,120)} 4.1852\left(joule\right)} = {\color{rgb(125,164,120)} 4.1852\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(therm\right)={\color{rgb(20,165,174)} x}\left(calorie\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 105480400.0} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.1852}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 105480400.0} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.1852} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 105480400.0} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.1852} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(105480400.0 = {\color{rgb(20,165,174)} x} \times 4.1852\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.1852 = 105480400.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.1852}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.1852 \times \dfrac{1.0}{4.1852} = 105480400.0 \times \dfrac{1.0}{4.1852}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.1852}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.1852}}} = 105480400.0 \times \dfrac{1.0}{4.1852}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{105480400.0}{4.1852}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx25203192.201\approx2.5203 \times 10^{7}\)
\(\text{Conversion Equation}\)
\(1.0\left(therm\right)\approx{\color{rgb(20,165,174)} 2.5203 \times 10^{7}}\left(calorie\right)\)
