Convert ton / hour to pound / second
Learn how to convert
1
ton / hour to
pound / second
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{ton}{hour}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{second}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{second}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{ton}{hour}\right) = {\color{rgb(89,182,91)} \dfrac{1.0}{3.6}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{second}\right)} = {\color{rgb(89,182,91)} \dfrac{1.0}{3.6}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{pound}{second}\right) = {\color{rgb(125,164,120)} 0.5\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{second}\right)} = {\color{rgb(125,164,120)} 0.5\left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{ton}{hour}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{second}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1.0}{3.6}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{second}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 0.5}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{second}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{1.0}{3.6}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 0.5} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1.0}{3.6}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 0.5} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{s}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{1.0}{3.6} = {\color{rgb(20,165,174)} x} \times 0.5\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 0.5 = \dfrac{1.0}{3.6}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{0.5}\right)\)
\({\color{rgb(20,165,174)} x} \times 0.5 \times \dfrac{1.0}{0.5} = \dfrac{1.0}{3.6} \times \dfrac{1.0}{0.5}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{0.5}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{0.5}}} = \dfrac{1.0 \times 1.0}{3.6 \times 0.5}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.0}{3.6 \times 0.5}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.5555555556\approx5.5556 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{ton}{hour}\right)\approx{\color{rgb(20,165,174)} 5.5556 \times 10^{-1}}\left(\dfrac{pound}{second}\right)\)
