Convert watt • hour to inch-pound force
Learn how to convert
1
watt • hour to
inch-pound force
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(watt \times hour\right)={\color{rgb(20,165,174)} x}\left(inch-pound \text{ } force\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(watt \times hour\right) = {\color{rgb(89,182,91)} 3.6 \times 10^{3}\left(joule\right)} = {\color{rgb(89,182,91)} 3.6 \times 10^{3}\left(J\right)}\)
\(\text{Right side: 1.0 } \left(inch-pound \text{ } force\right) = {\color{rgb(125,164,120)} 0.112984829027617\left(joule\right)} = {\color{rgb(125,164,120)} 0.112984829027617\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(watt \times hour\right)={\color{rgb(20,165,174)} x}\left(inch-pound \text{ } force\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 0.112984829027617}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 0.112984829027617} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 0.112984829027617} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(3.6 \times 10^{3} = {\color{rgb(20,165,174)} x} \times 0.112984829027617\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 0.112984829027617 = 3.6 \times 10^{3}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{0.112984829027617}\right)\)
\({\color{rgb(20,165,174)} x} \times 0.112984829027617 \times \dfrac{1.0}{0.112984829027617} = 3.6 \times 10^{3} \times \dfrac{1.0}{0.112984829027617}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{0.112984829027617}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{0.112984829027617}}} = 3.6 \times 10^{3} \times \dfrac{1.0}{0.112984829027617}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{3.6 \times 10^{3}}{0.112984829027617}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx31862.684849\approx3.1863 \times 10^{4}\)
\(\text{Conversion Equation}\)
\(1.0\left(watt \times hour\right)\approx{\color{rgb(20,165,174)} 3.1863 \times 10^{4}}\left(inch-pound \text{ } force\right)\)
