Convert ampere • hour to abcoulomb

Learn how to convert 1 ampere • hour to abcoulomb step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(ampere \times hour\right)={\color{rgb(20,165,174)} x}\left(abcoulomb\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(coulomb\right)\)
\(\text{Left side: 1.0 } \left(ampere \times hour\right) = {\color{rgb(89,182,91)} 3.6 \times 10^{3}\left(coulomb\right)} = {\color{rgb(89,182,91)} 3.6 \times 10^{3}\left(C\right)}\)
\(\text{Right side: 1.0 } \left(abcoulomb\right) = {\color{rgb(125,164,120)} 10.0\left(coulomb\right)} = {\color{rgb(125,164,120)} 10.0\left(C\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(ampere \times hour\right)={\color{rgb(20,165,174)} x}\left(abcoulomb\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \times {\color{rgb(89,182,91)} \left(coulomb\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 10.0}} \times {\color{rgb(125,164,120)} \left(coulomb\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \left(C\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 10.0} \cdot {\color{rgb(125,164,120)} \left(C\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 3.6 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(C\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 10.0} \times {\color{rgb(125,164,120)} \cancel{\left(C\right)}}\)
\(\text{Conversion Equation}\)
\(3.6 \times 10^{3} = {\color{rgb(20,165,174)} x} \times 10.0\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(3.6 \times {\color{rgb(255,204,153)} \cancelto{10^{2}}{10^{3}}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{10.0}}\)
\(\text{Simplify}\)
\(3.6 \times 10^{2} = {\color{rgb(20,165,174)} x}\)
Switch sides
\({\color{rgb(20,165,174)} x} = 3.6 \times 10^{2}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x} = 360 = 3.6 \times 10^{2}\)
\(\text{Conversion Equation}\)
\(1.0\left(ampere \times hour\right) = {\color{rgb(20,165,174)} 3.6 \times 10^{2}}\left(abcoulomb\right)\)

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