Convert foot-pound • pound force to (ohm • ampere) / second
Learn how to convert
1
foot-pound • pound force to
(ohm • ampere) / second
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(foot-pound \times pound \text{ } force\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ohm \times ampere}{second}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(joule\right)\)
\(\text{Left side: 1.0 } \left(foot-pound \times pound \text{ } force\right) = {\color{rgb(89,182,91)} 1.3558179483314\left(joule\right)} = {\color{rgb(89,182,91)} 1.3558179483314\left(J\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{ohm \times ampere}{second}\right) = {\color{rgb(125,164,120)} 1.0\left(joule\right)} = {\color{rgb(125,164,120)} 1.0\left(J\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(foot-pound \times pound \text{ } force\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ohm \times ampere}{second}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.3558179483314} \times {\color{rgb(89,182,91)} \left(joule\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 1.0}} \times {\color{rgb(125,164,120)} \left(joule\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.3558179483314} \cdot {\color{rgb(89,182,91)} \left(J\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 1.0} \cdot {\color{rgb(125,164,120)} \left(J\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.3558179483314} \cdot {\color{rgb(89,182,91)} \cancel{\left(J\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 1.0} \times {\color{rgb(125,164,120)} \cancel{\left(J\right)}}\)
\(\text{Conversion Equation}\)
\(1.3558179483314 = {\color{rgb(20,165,174)} x} \times 1.0\)
\(\text{Simplify}\)
\(1.3558179483314 = {\color{rgb(20,165,174)} x}\)
Switch sides
\({\color{rgb(20,165,174)} x} = 1.3558179483314\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx1.3558179483\approx1.3558\)
\(\text{Conversion Equation}\)
\(1.0\left(foot-pound \times pound \text{ } force\right)\approx{\color{rgb(20,165,174)} 1.3558}\left(\dfrac{ohm \times ampere}{second}\right)\)
