Convert pound-force to grave-force
Learn how to convert
1
pound-force to
grave-force
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(pound-force\right)={\color{rgb(20,165,174)} x}\left(grave-force\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(newton\right)\)
\(\text{Left side: 1.0 } \left(pound-force\right) = {\color{rgb(89,182,91)} 4.4482216152605\left(newton\right)} = {\color{rgb(89,182,91)} 4.4482216152605\left(N\right)}\)
\(\text{Right side: 1.0 } \left(grave-force\right) = {\color{rgb(125,164,120)} 9.80665\left(newton\right)} = {\color{rgb(125,164,120)} 9.80665\left(N\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(pound-force\right)={\color{rgb(20,165,174)} x}\left(grave-force\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 4.4482216152605} \times {\color{rgb(89,182,91)} \left(newton\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 9.80665}} \times {\color{rgb(125,164,120)} \left(newton\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 4.4482216152605} \cdot {\color{rgb(89,182,91)} \left(N\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 9.80665} \cdot {\color{rgb(125,164,120)} \left(N\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 4.4482216152605} \cdot {\color{rgb(89,182,91)} \cancel{\left(N\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 9.80665} \times {\color{rgb(125,164,120)} \cancel{\left(N\right)}}\)
\(\text{Conversion Equation}\)
\(4.4482216152605 = {\color{rgb(20,165,174)} x} \times 9.80665\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 9.80665 = 4.4482216152605\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{9.80665}\right)\)
\({\color{rgb(20,165,174)} x} \times 9.80665 \times \dfrac{1.0}{9.80665} = 4.4482216152605 \times \dfrac{1.0}{9.80665}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{9.80665}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{9.80665}}} = 4.4482216152605 \times \dfrac{1.0}{9.80665}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{4.4482216152605}{9.80665}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x} = 0.45359237\approx4.5359 \times 10^{-1}\)
\(\text{Conversion Equation}\)
\(1.0\left(pound-force\right)\approx{\color{rgb(20,165,174)} 4.5359 \times 10^{-1}}\left(grave-force\right)\)
